#include <iostream>
#include <cstdio>
using namespace std;

int main() {
    // Complete the code.
    int j, k ; 
    cin >> j >> k ;
    
    for(int n = j ; n <= k ; n++)
    {
        if( n < j) return 0 ;
        else if(n == 1) cout << "one\n" ;
        else if ( n == 2 ) cout << "two\n" ;
        else if ( n == 3 ) cout << "three\n" ;
        else if ( n == 4 ) cout << "four\n" ;
        else if ( n == 5 ) cout << "five\n" ;
        else if ( n == 6 ) cout << "six\n" ;
        else if ( n == 7 ) cout << "seven\n" ;
        else if ( n == 8 ) cout << "eight\n" ;
        else if ( n == 9 ) cout << "nine\n" ;
        else if( n % 2 == 0) cout << "even\n" ;
        else cout << "odd\n" ;
    }
    return 0;
}

A for loop is a programming language statement which allows code to be repeatedly executed.
The syntax is

for ( < expression_1 > ; < expression_2 > ; < expression_3 > )
    < statement >

• expression_1 is used for intializing variables which are generally used for controlling the terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables.

A sample loop is

for(int i = 0; i < 10; i++) {
    ...
}

In this challenge, you will use a for loop to increment a variable through a range.

Input Format
You will be given two positive integers, a and b (a<=b), separated by a newline.

Output Format
For each integer n in the inclusive interval [a,b]:
● If 1 <= n <= 9, then print the English representation of it in lowercase. That is "one" for 1, "two" for 2, and so on.
● Else if n > 9 and it is an even number, then print "even".
● Else if n > 9 and it is an odd number, then print "odd".

Note: [a,b] = { x ∈ Z | a <= X <= b } = {a, a+1 , a+2, a+3, ... b}

Sample Input
8
11

Sample Output
eight
nine
even
odd